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On a single-step or immediate-execution calculator, the user presses a key for each operation, calculating all the intermediate results, before the final value is shown. [ 1 ] [ 2 ] [ 3 ] On an expression or formula calculator , one types in an expression and then presses a key, such as "=" or "Enter", to evaluate the expression.
Microsoft Math contains features that are designed to assist in solving mathematics, science, and tech-related problems, as well as to educate the user. The application features such tools as a graphing calculator and a unit converter. It also includes a triangle solver and an equation solver that provides step-by-step solutions to each problem.
Symbolab is an answer engine [1] that provides step-by-step solutions to mathematical problems in a range of subjects. [2] It was originally developed by Israeli start-up company EqsQuest Ltd., under whom it was released for public use in 2011. In 2020, the company was acquired by American educational technology website Course Hero. [3] [4]
The Heaviside step function is an often-used step function. A constant function is a trivial example of a step function. Then there is only one interval, =. The sign function sgn(x), which is −1 for negative numbers and +1 for positive numbers, and is the simplest non-constant step function.
In reality, we can only use a finite number of these terms as it would take an infinite amount of computational time to make use of all of them. So let's suppose we use only three terms of the series, then e x ≈ 1 + x + x 2 2 ! {\displaystyle e^{x}\approx 1+x+{\frac {x^{2}}{2!}}}
The word problem for an algebra is then to determine, given two expressions (words) involving the generators and operations, whether they represent the same element of the algebra modulo the identities. The word problems for groups and semigroups can be phrased as word problems for algebras. [1]
A natural extension is to consider Boolean formulas of word equations, [4] in which also negation and disjunction is allowed. In fact, every system (and even every Boolean formula) of word equations, is equivalent to a single word equation. [4] Thus, many results on word equations generalise immediately to such systems (resp. formulas).
Start by labeling p 1, p 2 and p 3 as the corners of the Sierpiński triangle, and a random point v 1. Set v n+1 = 1 / 2 (v n + p r n), where r n is a random number 1, 2 or 3. Draw the points v 1 to v ∞. If the first point v 1 was a point on the Sierpiński triangle, then all the points v n lie on the Sierpiński triangle.