enow.com Web Search

Search results

  1. Results from the WOW.Com Content Network
  2. g-force - Wikipedia

    en.wikipedia.org/wiki/G-force

    For example: An acceleration of 1 g equates to a rate of change in velocity of approximately 35 km/h (22 mph) for each second that elapses. Therefore, if an automobile is capable of braking at 1 g and is traveling at 35 km/h, it can brake to a standstill in one second and the driver will experience a deceleration of 1 g. The automobile ...

  3. Gravitational acceleration - Wikipedia

    en.wikipedia.org/wiki/Gravitational_acceleration

    In physics, gravitational acceleration is the acceleration of an object in free fall within a vacuum ... 4.1 12.7 s: 57 km/h (35 mph) Saturn: 1.139 11.19 36.7 4.2 s:

  4. Space travel under constant acceleration - Wikipedia

    en.wikipedia.org/wiki/Space_travel_under...

    At a constant acceleration of 1 g, a rocket could travel the diameter of our galaxy in about 12 years ship time, and about 113,000 years planetary time. If the last half of the trip involves deceleration at 1 g, the trip would take about 24 years. If the trip is merely to the nearest star, with deceleration the last half of the way, it would ...

  5. Acceleration - Wikipedia

    en.wikipedia.org/wiki/Acceleration

    The acceleration of a falling body in the absence of resistances to motion is dependent only on the gravitational field strength g (also called acceleration due to gravity). By Newton's Second Law the force F g {\displaystyle \mathbf {F_{g}} } acting on a body is given by: F g = m g . {\displaystyle \mathbf {F_{g}} =m\mathbf {g} .}

  6. Gravity of Earth - Wikipedia

    en.wikipedia.org/wiki/Gravity_of_Earth

    The gravity g′ at depth d is given by g′ = g(1 − d/R) where g is acceleration due to gravity on the surface of the Earth, d is depth and R is the radius of the Earth. If the density decreased linearly with increasing radius from a density ρ 0 at the center to ρ 1 at the surface, then ρ(r) = ρ 0 − (ρ 0 − ρ 1) r / R, and the ...

  7. Peak ground acceleration - Wikipedia

    en.wikipedia.org/wiki/Peak_ground_acceleration

    Peak ground acceleration can be expressed in fractions of g (the standard acceleration due to Earth's gravity, equivalent to g-force) as either a decimal or percentage; in m/s 2 (1 g = 9.81 m/s 2); [7] or in multiples of Gal, where 1 Gal is equal to 0.01 m/s 2 (1 g = 981 Gal).

  8. Standard gravity - Wikipedia

    en.wikipedia.org/wiki/Standard_gravity

    This value was established by the third General Conference on Weights and Measures (1901, CR 70) and used to define the standard weight of an object as the product of its mass and this nominal acceleration. [1] [2] The acceleration of a body near the surface of the Earth is due to the combined effects of gravity and centrifugal acceleration ...

  9. Fourth, fifth, and sixth derivatives of position - Wikipedia

    en.wikipedia.org/wiki/Fourth,_fifth,_and_sixth...

    Snap, [6] or jounce, [2] is the fourth derivative of the position vector with respect to time, or the rate of change of the jerk with respect to time. [4] Equivalently, it is the second derivative of acceleration or the third derivative of velocity, and is defined by any of the following equivalent expressions: = ȷ = = =.