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Vapor pressure of n-butane. From formula: log 10 P m m H g = 6.83029 − 945.90 240.0 + T {\displaystyle \scriptstyle \log _{10}P_{mmHg}=6.83029-{\frac {945.90}{240.0+T}}} obtained from Lange's Handbook of Chemistry , 10th ed.
Here is a similar formula from the 67th edition of the CRC handbook. Note that the form of this formula as given is a fit to the Clausius–Clapeyron equation, which is a good theoretical starting point for calculating saturation vapor pressures: log 10 (P) = −(0.05223)a/T + b, where P is in mmHg, T is in kelvins, a = 38324, and b = 8.8017.
Values are given in terms of temperature necessary to reach the specified pressure. Valid results within the quoted ranges from most equations are included in the table for comparison. A conversion factor is included into the original first coefficients of the equations to provide the pressure in pascals (CR2: 5.006, SMI: -0.875).
(760 mmHg = 101.325 kPa = 1.000 atm = normal pressure) This example shows a severe problem caused by using two different sets of coefficients. The described vapor pressure is not continuous—at the normal boiling point the two sets give different results. This causes severe problems for computational techniques which rely on a continuous vapor ...
log 10 of Chloroform vapor pressure. Uses formula: log e P m m H g = {\displaystyle \scriptstyle \log _{e}P_{mmHg}=} log e ( 760 101.325 ) − 10.07089 log e ( T + 273.15 ) − 6351.140 T + 273.15 + 81.14393 + 9.127608 × 10 − 6 ( T + 273.15 ) 2 {\displaystyle \scriptstyle \log _{e}({\frac {760}{101.325}})-10.07089\log _{e}(T+273. ...
This page provides supplementary chemical data ... vapor pressure at 20 °C = 0.556 mbar = 0.417 mmHg [2] log 10 of dimethyl sulfoxide vapor pressure. Uses formula ...
The handling of this chemical may incur notable safety precautions. It is highly recommend that you seek the Material Safety Datasheet ( MSDS ) for this chemical from a reliable source such as eChemPortal , and follow its directions.
Formula from Lange's Handbook of Chemistry, 10th ed. log 10 of acetic acid vapor pressure vs. temperature. Uses formula: log 10 P m m H g = 7.80307 − 1651.2 225 + T {\displaystyle \scriptstyle \log _{10}P_{mmHg}=7.80307-{\frac {1651.2}{225+T}}} for T = 0 to 36 °C log 10 P m m H g = 7.18807 − 1416.7 211 + T {\displaystyle ...