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The solution = is in fact a valid solution to the original equation; but the other solution, =, has disappeared. The problem is that we divided both sides by x {\displaystyle x} , which involves the indeterminate operation of dividing by zero when x = 0. {\displaystyle x=0.}
The meaning of the expression should be the solution x of the equation =. But in the ring Z /6 Z , 2 is a zero divisor . This equation has two distinct solutions, x = 1 and x = 4 , so the expression 2 2 {\textstyle {\frac {2}{2}}} is undefined .
If the initial amount p leads to a percent change x, and the second percent change is y, then the final amount is p (1 + 0.01 x)(1 + 0.01 y). To change the above example, after an increase of x = 10 percent and decrease of y = −5 percent , the final amount, $209, is 4.5% more than the initial amount of $200.
A discretization is a sequence of cut-points, and the values of pieces between these cut-points (for example: a protocol for two agents might require each agent to report a sequence of three cut-points (0,x,1) where the values of (0,x) and (x,1) are 1/2). [16]
A quartic equation where a 3 and a 1 are equal to 0 takes the form a 0 x 4 + a 2 x 2 + a 4 = 0 {\displaystyle a_{0}x^{4}+a_{2}x^{2}+a_{4}=0\,\!} and thus is a biquadratic equation , which is easy to solve: let z = x 2 {\displaystyle z=x^{2}} , so our equation becomes
It is the same concept as volume percent (vol%) except that the latter is expressed with a denominator of 100, e.g., 18%. The volume fraction coincides with the volume concentration in ideal solutions where the volumes of the constituents are additive (the volume of the solution is equal to the sum of the volumes of its ingredients).
[3] [4] Expressions can be evaluated or simplified by replacing operations that appear in them with their result. For example, the expression 8 × 2 − 5 {\displaystyle 8\times 2-5} simplifies to 16 − 5 {\displaystyle 16-5} , and evaluates to 11. {\displaystyle 11.}
In the division of 42 by 5, we have: 42 = 8 × 5 + 2, and since 2 < 5/2, 2 is both the least positive remainder and the least absolute remainder. In these examples, the (negative) least absolute remainder is obtained from the least positive remainder by subtracting 5, which is d. This holds in general.