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Chheoki is at a distance of 10 km from Prayagraj Junction on the Howrah–Delhi main line. Trains that bypass Prayagraj Junction and which come from Jabalpur and go towards Mughalsarai usually stop at Chheoki. To reduce the load on the main junction, trains were shifted to Chheoki. [3]
The opening of the Curzon Bridge, across the Ganges, in 1902, linked Prayagraj to regions north of or beyond the Ganges. [5] The Varanasi–Prayagraj City (Rambagh) line was constructed as a metre-gauge line by the Bengal and North Western Railway between 1899 and 1913. It was converted to broad gauge in 1993–94.
Euclid proved that the area of a triangle is half that of a parallelogram with the same base and height in his book Elements in 300 BCE. [1] In 499 CE Aryabhata, used this illustrated method in the Aryabhatiya (section 2.6). [2] Although simple, this formula is only useful if the height can be readily found, which is not always the case.
If a point is on a sideline of the reference triangle, its corresponding trilinear coordinate is 0. If an exterior point is on the opposite side of a sideline from the interior of the triangle, its trilinear coordinate associated with that sideline is negative. It is impossible for all three trilinear coordinates to be non-positive.
The 12417 / 12418 Prayagraj S. F Express is a daily Overnight Superfast Express VVIP train which runs between the cities of Prayagraj (earlier known as Allahabad) and New Delhi, India. Prayagraj Express along with Shram Shakti Express , Shiv Ganga Express , Lucknow Mail and Shaan-e-Bhopal Express enjoys highest priority all over the route.
This formula generalizes Heron's formula for the area of a triangle. A triangle may be regarded as a quadrilateral with one side of length zero. From this perspective, as d approaches zero, a cyclic quadrilateral converges into a cyclic triangle (all triangles are cyclic), and Brahmagupta's formula simplifies to Heron's formula.
One of the sensors is typically a digital camera device, and the other one can also be a camera or a light projector. The projection centers of the sensors and the considered point on the object's surface define a (spatial) triangle. Within this triangle, the distance between the sensors is the base b and must be known. By determining the ...
If is the radius of the incircle of the triangle, then the triangle can be broken into three triangles of equal altitude and bases , , and . Their combined area is A = 1 2 a r + 1 2 b r + 1 2 c r = r s , {\displaystyle A={\tfrac {1}{2}}ar+{\tfrac {1}{2}}br+{\tfrac {1}{2}}cr=rs,} where s = 1 2 ( a + b + c ...