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These are the only cases where the host opens door 3, so the conditional probability of winning by switching given the host opens door 3 is 1/3 / 1/3 + q/3 which simplifies to 1 / 1 + q . Since q can vary between 0 and 1 this conditional probability can vary between 1 / 2 and 1. This means even without constraining the ...
In game theory, "guess 2 / 3 of the average" is a game where players simultaneously select a real number between 0 and 100, inclusive. The winner of the game is the player(s) who select a number closest to 2 / 3 of the average of numbers chosen by all players. [1]
In mathematics, a combination is a selection of items from a set that has distinct members, such that the order of selection does not matter (unlike permutations).For example, given three fruits, say an apple, an orange and a pear, there are three combinations of two that can be drawn from this set: an apple and a pear; an apple and an orange; or a pear and an orange.
So there is now a 1 in 48 chance of predicting this number. Thus for each of the 49 ways of choosing the first number there are 48 different ways of choosing the second. This means that the probability of correctly predicting 2 numbers drawn from 49 in the correct order is calculated as 1 in 49 × 48. On drawing the third number there are only ...
Even-Odd as an early form of roulette. This game was known by the Greeks (as artiazein) and Romans (as ludere par impar).In the 1858 Krünitzlexikon it says: [3] "The game Odds and Evens was very common amongst the Romans and was played either with tali, tesseris, or money and known as "Alea maior", or with nuts, beans and almonds and known as "Alea minor"."
[3] A fast way to determine whether two numbers are coprime is given by the Euclidean algorithm and its faster variants such as binary GCD algorithm or Lehmer's GCD algorithm. The number of integers coprime with a positive integer n, between 1 and n, is given by Euler's totient function, also known as Euler's phi function, φ(n).
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The 1/3–2/3 conjecture states that, at each step, one may choose a comparison to perform that reduces the remaining number of linear extensions by a factor of 2/3; therefore, if there are E linear extensions of the partial order given by the initial information, the sorting problem can be completed in at most log 3/2 E additional comparisons.