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Parsons' programming puzzles became known as Parsons puzzles [2] and then Parsons problems. [3] Parsons problems have become popular as they are easier to grade than written code while capturing the students problem solving ability shown in a code creation process.
More generally, the smallest enclosing ball of points in d dimensions forms an LP-type problem of combinatorial dimension d + 1. The smallest circle problem can be generalized to the smallest ball enclosing a set of balls, [3] to the smallest ball that touches or surrounds each of a set of balls, [4] to the weighted 1-center problem, [5] or to ...
So Phase 1 ends with the following reduced preference lists: (for example we cross out 5 for 1: because 1: gets at least 6) 1 : 3 4 2 6 5 2 : 6 5 4 1 3
The secretary problem demonstrates a scenario involving optimal stopping theory [1] [2] that is studied extensively in the fields of applied probability, statistics, and decision theory. It is also known as the marriage problem , the sultan's dowry problem , the fussy suitor problem , the googol game , and the best choice problem .
The study of polyomino tilings largely concerns two classes of problems: to tile a rectangle with congruent tiles, and to pack one of each n-omino into a rectangle. A classic puzzle of the second kind is to arrange all twelve pentominoes into rectangles sized 3×20, 4×15, 5×12 or 6×10.
As already remarked, most sources in the topic of probability, including many introductory probability textbooks, solve the problem by showing the conditional probabilities that the car is behind door 1 and door 2 are 1 / 3 and 2 / 3 (not 1 / 2 and 1 / 2 ) given that the contestant initially picks door 1 and the ...
So, the desired area A is A 1 + (A 2 − A 3 + A 4) · 2. The area(s) required to be computed are between two quadratic curves, and will necessarily be an integral or difference of integrals. The primary parameters of the problem are , the tether length defined to be 160yds, and , the radius
If the fraction of time that is required by each task totals less than 5/6 of the total time, a solution always exists, but some pinwheel scheduling problems whose tasks use a total of slightly more than 5/6 of the total time do not have solutions. Certain formulations of the pinwheel scheduling problem are NP-hard.