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Manganese(II) chloride is the dichloride salt of manganese, MnCl 2.This inorganic chemical exists in the anhydrous form, as well as the dihydrate (MnCl 2 ·2H 2 O) and tetrahydrate (MnCl 2 ·4H 2 O), with the tetrahydrate being the most common form.
Row 1. Molar mass of species, density at 298.15 K, ΔH° form 298.15, S° 298.15. and the upper temperature limit for the file. Row 2. Number of C p equations required. Here, three because of three species phases. Row 3. Values of the five parameters for the first C p equation; temperature limit for the equation. Row 4.
molar Planck constant 3.990 312 712 893 4314 × 10 −10 J⋅s⋅mol −1: 0 [52] = molar mass of carbon-12: 12.000 000 0126 (37) × 10 −3 kg⋅mol −1: 3.1 × 10 −10 [53] = / atomic mass constant: 1.660 539 068 92 (52) × 10 −27 kg
Note that the especially high molar values, as for paraffin, gasoline, water and ammonia, result from calculating specific heats in terms of moles of molecules. If specific heat is expressed per mole of atoms for these substances, none of the constant-volume values exceed, to any large extent, the theoretical Dulong–Petit limit of 25 J⋅mol ...
The gas constant occurs in the ideal gas law: = = where P is the absolute pressure, V is the volume of gas, n is the amount of substance, m is the mass, and T is the thermodynamic temperature. R specific is the mass-specific gas constant. The gas constant is expressed in the same unit as molar heat.
The ideal gas equation can be rearranged to give an expression for the molar volume of an ideal gas: = = Hence, for a given temperature and pressure, the molar volume is the same for all ideal gases and is based on the gas constant: R = 8.314 462 618 153 24 m 3 ⋅Pa⋅K −1 ⋅mol −1, or about 8.205 736 608 095 96 × 10 −5 m 3 ⋅atm⋅K ...
The molar volume of gases around STP and at atmospheric pressure can be calculated with an accuracy that is usually sufficient by using the ideal gas law. The molar volume of any ideal gas may be calculated at various standard reference conditions as shown below: V m = 8.3145 × 273.15 / 101.325 = 22.414 dm 3 /mol at 0 °C and 101.325 kPa
How much gas is present could be specified by giving the mass instead of the chemical amount of gas. Therefore, an alternative form of the ideal gas law may be useful. The chemical amount, n (in moles), is equal to total mass of the gas (m) (in kilograms) divided by the molar mass, M (in kilograms per mole): =.