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Check why the first fopen call fails; check errno.It is likely some allocation happens in the first fopen call, even though it ends up failing.
You may be trying to free a pointer that wasn't allocated by malloc (or delete an object that wasn't created by new) or you may be trying to free/delete such an object more than once. You may be overflowing a buffer or otherwise writing to memory to which you shouldn't be writing, causing heap corruption.
When you encounter errors, start with the 1. one , it might be the cause of the following errors. ==17917== Invalid write of size 8 ==17917== at 0x5E53E04: __GI ...
I've read through similar problems, but I can't find anything that specifically addresses my problem (or I simply don't understand the other solutions) I am trying to implement a template Stack cl...
The free function causes the space pointed to by ptr to be deallocated, that is, made available for further allocation. If ptr is a null pointer, no action occurs. Otherwise, if the argument does not match a pointer earlier returned by the calloc, malloc, or realloc function, or if the space has been deallocated by a call to free or realloc ...
It just depends on what memory address you get at runtime when you dereference and/or assign to f[i][j].The address in all cases is "undefined", so sometimes it will resolve to an address your program can write to, which is still going to cause corruption but won't necessarily crash immediately, and sometimes it'll be a location you have no read or write access to.
As part of an exercise, I am modifying this class that represents a different way of creating arrays: template<class T> class Array { public: Array(int size, T defaultvalue) : _size(size) ...
You're trying to free memory that's not heap memory. Don't do that. You're trying to free the inside of a block of memory. When you have in fact allocated a block of memory, you can only free it from the pointer returned by malloc. That is to say, only from the beginning of the block. You can't free a portion of the block from the inside.
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When the first object goes out of scope and is destructed, it will free the string data, leaving the other object with an invalid pointer to data that is no longer owned by your process. When that second object is destructed it will try to free the already free'd data. And this is only when you save and load the object in a single process.