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The BBP formula gives rise to a spigot algorithm for computing the nth base-16 (hexadecimal) digit of π (and therefore also the 4nth binary digit of π) without computing the preceding digits. This does not compute the nth decimal digit of π (i.e., in base 10). [3]
The Chudnovsky algorithm is a fast method for calculating the digits of π, based on Ramanujan's π formulae.Published by the Chudnovsky brothers in 1988, [1] it was used to calculate π to a billion decimal places.
The arithmetic–geometric mean of two numbers, a 0 and b 0, is found by calculating the limit of the sequences + = +, + =, which both converge to the same limit. If = and = then the limit is () where () is the complete elliptic integral of the first kind
A variant of the spigot approach uses an algorithm which can be used to compute a single arbitrary digit of the transcendental without computing the preceding digits: an example is the Bailey–Borwein–Plouffe formula, a digit extraction algorithm for π which produces base 16 digits. The inevitable truncation of the underlying infinite ...
Pages in category "Pi algorithms" The following 17 pages are in this category, out of 17 total. This list may not reflect recent changes. A. ... Code of Conduct;
Finds a formula that allows the nth hexadecimal digit of pi to be calculated without calculating the preceding digits. 28 August 1995 Yasumasa Kanada and Daisuke Takahashi: HITAC S-3800/480 (dual CPU) [36] [37] 56.74 hours? 4,294,960,000: 11 October 1995 Yasumasa Kanada and Daisuke Takahashi: HITAC S-3800/480 (dual CPU) [38] [37] 116.63 hours ...
While the PiHex project calculated the least significant digits of π ever attempted at the time in any base, the second place is held by Peter Trueb who computed some 22+ trillion digits in 2016 and third place by houkouonchi who derived the 13.3 trillionth digit in base 10.
Thus, a problem on elements is reduced to two recursive problems on / elements (to find the pivot) and at most / elements (after the pivot is used). The total size of these two recursive subproblems is at most 9 n / 10 {\displaystyle 9n/10} , allowing the total time to be analyzed as a geometric series adding to O ( n ) {\displaystyle O(n)} .