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In English, I feel, length is usually in the “most important” dimension while width is horizontal and at right-angles to the length. Neither is usually vertical: that is the height. The “most important” dimension is often that in which you move or look, or the longest. Length can also apply to time, while width cannot.
Hence the width of the rectangle, is, effectively the perpendicular from its base to its top. So for rectangles, we can use the formula . A = length * width. Note: I think width, length, base and height are loosely defined in this case, but I hope you get the general idea. You can call a rectangles length "base" and its width "height" if you want.
$\begingroup$ How many tiles your friend will need is actually a more complicated question than just measuring the area, because if the sides of the rectangle to be tiled are not integer multiples of the size of one tile, you have to break tiles to fit and you need to figure out how much of the area of the broken tiles you actually will be able to use.
Let the length of the rectangle be l l and the width be w w. We know the area of the rectangle is A = lw (1) (1) A = l w. Now it is given that l w = 241625 ⇒ l = 241625w (2) (2) l w = 241 625 ⇒ l = 241 625 w. Now substituting (2) (2) in (1) (1), we have, A = 241 625w2 = 1500 A = 241 625 w 2 = 1500. w = 1500 × 625 241− −−−−−− ...
Calculate height or width of rectangle given its area and height or width. 0 Calculte new width and height of the video based on the original width, height and ratio
I understand $\text{length} \times \text{width} = \text{area}$, but outside of this information I don't understand how they got to this solution from the given information in the problem. algebra-precalculus
Is it possible to find the width and length of a rectangle by just know the diagonal? Like if the diagonal was 25, what would be the side lengths? Any help is appreciated! EDIT: From the comments and solutions this is not possible. Thanks for the explanations!
Technically, a point is dimensionless. It does not have a length, width, or height. It is an imaginary construct. If you are wondering why, despite a point being imaginary and having no dimensions, you can "see" it, it is because if you are to mark a point on a 2D graph on a piece of paper, it has all 3 of those dimensions.
Well, I know, it's easy. We did it in class some time ago and I forgot it, I'm stupid because I can't figure it out: E.g. I have a 32" TV with 16:9 ratio and I want to know its width and height. ...
Wikipedia article on hexagons states that a height-to-width ratio of a regular hexagon is 1:1.1547005. So although trigonometry can do this, you can also use: a = b * 0.8660254