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Alcohol oxidation is a collection of oxidation reactions in organic chemistry that convert alcohols to aldehydes, ketones, carboxylic acids, and esters. The reaction mainly applies to primary and secondary alcohols. Secondary alcohols form ketones, while primary alcohols form aldehydes or carboxylic acids. [1] A variety of oxidants can be used.
The only hydrates with stable melting points are NaOH·H 2 O (65.10 °C) and NaOH·3.5H 2 O (15.38 °C). The other hydrates, except the metastable ones NaOH·3H 2 O and NaOH·4H 2 O (β) can be crystallized from solutions of the proper composition, as listed above. However, solutions of NaOH can be easily supercooled by many degrees, which ...
Sodium ethoxide, also referred to as sodium ethanolate, is the ionic, organic compound with the formula CH 3 CH 2 ONa, C 2 H 5 O Na, or NaOEt (Et = ethyl). It is a white solid, although impure samples appear yellow or brown. It dissolves in polar solvents such as ethanol. It is commonly used as a strong base. [2]
In one simplified version, the saponification of stearin gives sodium stearate. C 3 H 5 (O 2 C(CH 2) 16 CH 3) 3 + 3 NaOH → C 3 H 5 (OH) 3 + 3 NaO 2 C(CH 2) 16 CH 3. This process is the main industrial method for producing glycerol (C 3 H 5 (OH) 3). Some soap-makers leave the glycerol in the soap. Others precipitate the soap by salting it out ...
An aldol condensation is a condensation reaction in organic chemistry in which two carbonyl moieties (of aldehydes or ketones) react to form a β-hydroxyaldehyde or β-hydroxyketone (an aldol reaction), and this is then followed by dehydration to give a conjugated enone. The overall reaction equation is as follows (where the Rs can be H)
2 H 2 O + 2e − → H 2 + 2OH −. The ion-permeable ion-exchange membrane at the center of the cell allows only the sodium ions (Na +) to pass to the second chamber where they react with the hydroxide ions to produce caustic soda (NaOH) (B in figure): [1] Na + + OH − → NaOH The overall reaction for the electrolysis of brine is thus: 2NaCl ...
For example, sodium hydroxide, NaOH, is a strong base. NaOH(aq) → Na + (aq) + OH − (aq) Therefore, when a strong acid reacts with a strong base the neutralization reaction can be written as H + + OH − → H 2 O. For example, in the reaction between hydrochloric acid and sodium hydroxide the sodium and chloride ions, Na + and Cl − take ...
Unlike acid-catalyzed ester hydrolysis, it is not an equilibrium reaction and proceeds to completion. Hydroxide ion attacks the carbonyl carbon to give a tetrahedral intermediate, which then expels an alkoxide ion. The resulting carboxylic acid quickly protonates the alkoxide ion to give a carboxylate ion and an alcohol. [1]