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  2. Euler method - Wikipedia

    en.wikipedia.org/wiki/Euler_method

    The backward Euler method is an implicit method, meaning that the formula for the backward Euler method has + on both sides, so when applying the backward Euler method we have to solve an equation. This makes the implementation more costly.

  3. Numerical methods for ordinary differential equations - Wikipedia

    en.wikipedia.org/wiki/Numerical_methods_for...

    Numerical methods for solving first-order IVPs often fall into one of two large categories: [5] linear multistep methods, or Runge–Kutta methods. A further division can be realized by dividing methods into those that are explicit and those that are implicit.

  4. Newton's method - Wikipedia

    en.wikipedia.org/wiki/Newton's_method

    The initial guess will be x 0 = 1 and the function will be f(x) = x 22 so that f ′ (x) = 2x. Each new iteration of Newton's method will be denoted by x1 . We will check during the computation whether the denominator ( yprime ) becomes too small (smaller than epsilon ), which would be the case if f ′ ( x n ) ≈ 0 , since otherwise a ...

  5. Baker percentage - Wikipedia

    en.wikipedia.org/wiki/Baker_percentage

    For example, in a recipe that calls for 10 pounds of flour and 5 pounds of water, the corresponding baker's percentages are 100% for the flour and 50% for the water. Because these percentages are stated with respect to the weight of flour rather than with respect to the weight of all ingredients, the sum of these percentages always exceeds 100%.

  6. Small-angle approximation - Wikipedia

    en.wikipedia.org/wiki/Small-angle_approximation

    [1] [2] One reason for this is that they can greatly simplify differential equations that do not need to be answered with absolute precision. There are a number of ways to demonstrate the validity of the small-angle approximations. The most direct method is to truncate the Maclaurin series for each of the trigonometric functions.

  7. Percentage - Wikipedia

    en.wikipedia.org/wiki/Percentage

    ⁠ 50 / 100 ⁠ × ⁠ 40 / 100 ⁠ = 0.50 × 0.40 = 0.20 = ⁠ 20 / 100 ⁠ = 20%. It is not correct to divide by 100 and use the percent sign at the same time; it would literally imply division by 10,000. For example, 25% = ⁠ 25 / 100 ⁠ = 0.25, not ⁠ 25% / 100 ⁠, which actually is ⁠ 25 ⁄ 100 / 100 ⁠ = 0.0025.

  8. Jacobi method - Wikipedia

    en.wikipedia.org/wiki/Jacobi_method

    Input: initial guess x (0) to the solution, (diagonal dominant) matrix A, right-hand side vector b, convergence criterion Output: solution when convergence is reached Comments: pseudocode based on the element-based formula above k = 0 while convergence not reached do for i := 1 step until n do σ = 0 for j := 1 step until n do if j ≠ i then ...

  9. Bisection method - Wikipedia

    en.wikipedia.org/wiki/Bisection_method

    A few steps of the bisection method applied over the starting range [a 1;b 1].The bigger red dot is the root of the function. In mathematics, the bisection method is a root-finding method that applies to any continuous function for which one knows two values with opposite signs.