Search results
Results from the WOW.Com Content Network
Multiplying the equation by a 2 and dividing by b 3 gives: + =. Substituting y = ax/b gives: + = which could now be solved by looking up the n 3 + n 2 table to find the value closest to the right-hand side. The Babylonians accomplished this without algebraic notation, showing a remarkable depth of understanding.
It is also used for graphing quadratic functions, deriving the quadratic formula, and more generally in computations involving quadratic polynomials, for example in calculus evaluating Gaussian integrals with a linear term in the exponent, [2] and finding Laplace transforms. [3] [4]
Babylonian clay tablet YBC 7289 with annotations. The diagonal displays an approximation of the square root of 2 in four sexagesimal figures, 1 24 51 10, which is good to about six decimal digits. 1 + 24/60 + 51/60 2 + 10/60 3 = 1.41421296... The tablet also gives an example where one side of the square is 30, and the resulting diagonal is 42 ...
The ratio p/q takes its greatest value, 12/5=2.4, in Row 1 of the table, and is therefore always less than +, a condition which guarantees that p 2 − q 2 is the long leg and 2pq is the short leg of the triangle and which, in modern terms, implies that the angle opposite the leg of length p 2 − q 2 is less than 45°.
The quadratic equation on a number can be solved using the well-known quadratic formula, which can be derived by completing the square. That formula always gives the roots of the quadratic equation, but the solutions are expressed in a form that often involves a quadratic irrational number, which is an algebraic fraction that can be evaluated ...
The solutions of the quadratic equation ax 2 + bx + c = 0 correspond to the roots of the function f(x) = ax 2 + bx + c, since they are the values of x for which f(x) = 0. If a , b , and c are real numbers and the domain of f is the set of real numbers, then the roots of f are exactly the x - coordinates of the points where the graph touches the ...
Then they can be divided out and the resulting quadratic equation solved. In general, there exist only four possible cases of quartic equations with multiple roots, which are listed below: [3] Multiplicity-4 (M4): when the general quartic equation can be expressed as () =, for some real number. This case can always be reduced to a biquadratic ...
A similar but more complicated method works for cubic equations, which have three resolvents and a quadratic equation (the "resolving polynomial") relating and , which one can solve by the quadratic equation, and similarly for a quartic equation (degree 4), whose resolving polynomial is a cubic, which can in turn be solved. [14]