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  2. What is the derivative of sec x? - Socratic

    socratic.org/questions/what-is-the-derivative-of-sec-x

    To find the derivative of secant, we could either use the limit definition of the derivative (which would take a very long time) or the definition of secant itself: #secx=1/cosx# We know #d/dxcosx=-sinx# - keep that in mind because we're going to need it. Our problem is: #d/dxsecx# Since #secx=1/cosx#, we can write this as: #d/dx1/cosx#

  3. Derivatives of y=sec (x), y=cot (x), y= csc (x) - Calculus -...

    socratic.org/.../derivatives-of-y-sec-x-y-cot-x-y-csc-x

    The derivatives of \sec(x), \cot(x), and \csc(x) can be calculated by using the quotient rule of differentiation together with the identities \sec(x)=\frac{1}{\cos(x ...

  4. What is the derivative of #sec^-1(x)#? - Socratic

    socratic.org/questions/what-is-the-derivative-of-sec-1-x

    Let y=sec^{-1}x. by rewriting in terms of secant, => sec y=x by differentiating with respect to x, => sec y tan y cdot y'=1 by dividing by sec y tan y, => y' = 1/{sec y tan y} since sec y =x and tan x = sqrt{sec^2 y -1}=sqrt{x^2-1} => y'=1/{x sqrt{x^2-1}} Hence, d/dx(sec^{-1}x)=1/{x sqrt{x^2-1}} I hope that this was helpful.

  5. Find the Derivative of sec x using first principle? - Socratic

    socratic.org/questions/find-the-derivative-of-sec-x-using-first-principle

    Define the function: # f(x)=secx # Using the limit definition of the derivative, we have: # f'(x) = lim_(h rarr 0) (f(x+h)-f(x))/h #

  6. What is the derivative of #sec^2(x)#? - Socratic

    socratic.org/questions/what-is-the-derivative-of-sec-2-x

    Callum H. Dec 17, 2014. Use the Chain rule. d dx (sec2(x)) = 2sec(x) ⋅ sec(x)tan(x) = 2sec2(x)tan(x) Answer link. iOS.

  7. What is the derivative of y=sec^2(2x)? + Example - Socratic

    socratic.org/questions/what-is-the-derivative-of-y-sec-2-2x

    The function y = sec^2(2x) can be rewritten as y = sec(2x)^2 or y = g(x)^2 which should clue us in as a good candidate for the power rule. The power rule: dy/dx = n* g(x)^(n-1) * d/dx(g(x)) where g(x) = sec(2x) and n=2 in our example. Plugging these values into the power rule gives us dy/dx = 2 * sec(2x) ^ 1 *d/dx(g(x)) Our only unknown remains d/dx(g(x)). To find the derivative of g(x) = sec ...

  8. What is the derivative of #sec(x^2)#? - Socratic

    socratic.org/questions/what-is-the-derivative-of-sec-x-2

    2) The derivative of the inner function: d dx x2 = 2x. 3) Combining the two steps to give the actual derivative: d dx sec(x2) = sec(x2)tan(x2)2x. Answer link. Answer d/dx sec (x^2)= sec (x^2)tan (x^2)2x Explanation To solve this question, you would need to use the chain rule (and later on, the quotient rule as well).

  9. What is Derivatives of #y=sec(x)# - Socratic

    socratic.org/questions/what-is-derivatives-of-y-sec-x

    You could memorize this, but you can work it out too by knowing some trig properties. The trig properties we will use are: sec(x) = 1 cos(x) and sinx cosx = tanx. Deriving: d dx sec(x) = d dx 1 cos(x) = cos(x)(0) −1(−sin(x)) cos(x)cos(x) (using the quotient rule)

  10. What is the Derivative of y = sec^2(x)? Maths Q&A - BYJU'S

    byjus.com/question-answer/what-is-the-derivative-of-y-sec-2-x

    Find the Derivative of y = sec 2 (x). Differentiate both sides w.r.t x using chain rule. d y d x = d d x sec 2 x = 2 sec x d d x sec x chain rule : d d x f g x = d d x f g x × d d x g ( x ) Power rule : d d x x n = n x n - 1 = 2 sec x × sec x tan x = 2 sec 2 x tan x

  11. How do you find the derivative of secx tanx? - Socratic

    socratic.org/questions/how-do-you-find-the-derivative-of-secx-tanx

    Use the product rule and derivatives of trigonometric functions. d/dx(secx tanx) = d/dx(secx) tanx + secx d/dx(tanx) = (secxtanx)tanx+secx(sec^2x) = sec tan^2x + sec^3x = secx(tan^2x+sec^2x)