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To find the derivative of secant, we could either use the limit definition of the derivative (which would take a very long time) or the definition of secant itself: #secx=1/cosx# We know #d/dxcosx=-sinx# - keep that in mind because we're going to need it. Our problem is: #d/dxsecx# Since #secx=1/cosx#, we can write this as: #d/dx1/cosx#
The derivatives of \sec(x), \cot(x), and \csc(x) can be calculated by using the quotient rule of differentiation together with the identities \sec(x)=\frac{1}{\cos(x ...
Let y=sec^{-1}x. by rewriting in terms of secant, => sec y=x by differentiating with respect to x, => sec y tan y cdot y'=1 by dividing by sec y tan y, => y' = 1/{sec y tan y} since sec y =x and tan x = sqrt{sec^2 y -1}=sqrt{x^2-1} => y'=1/{x sqrt{x^2-1}} Hence, d/dx(sec^{-1}x)=1/{x sqrt{x^2-1}} I hope that this was helpful.
Define the function: # f(x)=secx # Using the limit definition of the derivative, we have: # f'(x) = lim_(h rarr 0) (f(x+h)-f(x))/h #
Callum H. Dec 17, 2014. Use the Chain rule. d dx (sec2(x)) = 2sec(x) ⋅ sec(x)tan(x) = 2sec2(x)tan(x) Answer link. iOS.
The function y = sec^2(2x) can be rewritten as y = sec(2x)^2 or y = g(x)^2 which should clue us in as a good candidate for the power rule. The power rule: dy/dx = n* g(x)^(n-1) * d/dx(g(x)) where g(x) = sec(2x) and n=2 in our example. Plugging these values into the power rule gives us dy/dx = 2 * sec(2x) ^ 1 *d/dx(g(x)) Our only unknown remains d/dx(g(x)). To find the derivative of g(x) = sec ...
2) The derivative of the inner function: d dx x2 = 2x. 3) Combining the two steps to give the actual derivative: d dx sec(x2) = sec(x2)tan(x2)2x. Answer link. Answer d/dx sec (x^2)= sec (x^2)tan (x^2)2x Explanation To solve this question, you would need to use the chain rule (and later on, the quotient rule as well).
You could memorize this, but you can work it out too by knowing some trig properties. The trig properties we will use are: sec(x) = 1 cos(x) and sinx cosx = tanx. Deriving: d dx sec(x) = d dx 1 cos(x) = cos(x)(0) −1(−sin(x)) cos(x)cos(x) (using the quotient rule)
Find the Derivative of y = sec 2 (x). Differentiate both sides w.r.t x using chain rule. d y d x = d d x sec 2 x = 2 sec x d d x sec x chain rule : d d x f g x = d d x f g x × d d x g ( x ) Power rule : d d x x n = n x n - 1 = 2 sec x × sec x tan x = 2 sec 2 x tan x
Use the product rule and derivatives of trigonometric functions. d/dx(secx tanx) = d/dx(secx) tanx + secx d/dx(tanx) = (secxtanx)tanx+secx(sec^2x) = sec tan^2x + sec^3x = secx(tan^2x+sec^2x)