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In general, solving these nonlinear equations presents a formidable challenge because of the huge range over which the free concentrations may vary. At the beginning, values for the free concentrations must be estimated. Then, these values are refined, usually by means of Newton–Raphson iterations. The logarithms of the free concentrations ...
The equilibrium constant of a chemical reaction is the value of its reaction quotient at chemical equilibrium, a state approached by a dynamic chemical system after sufficient time has elapsed at which its composition has no measurable tendency towards further change. For a given set of reaction conditions, the equilibrium constant is ...
All chemical transformations pass through an unstable structure called the transition state, which is poised between the chemical structures of the substrates and products. The transition states for chemical reactions are proposed to have lifetimes near 10 −13 seconds, on the order of the time of a single bond vibration. No physical or ...
With the catalyst, the energy required to enter transition state decreases, thereby decreasing the energy required to initiate the reaction. A substance that modifies the transition state to lower the activation energy is termed a catalyst; a catalyst composed only of protein and (if applicable) small molecule cofactors is termed an enzyme.
A chemical reaction may undergo different reaction mechanisms at different temperatures. [13] In this case, a Van 't Hoff plot with two or more linear fits may be exploited. Each linear fit has a different slope and intercept, which indicates different changes in enthalpy and entropy for each distinct mechanisms.
When pure substances (liquids or solids) are involved in equilibria their activities do not appear in the equilibrium constant [14] because their numerical values are considered one. Applying the general formula for an equilibrium constant to the specific case of a dilute solution of acetic acid in water one obtains CH 3 CO 2 H + H 2 O ⇌ CH 3 ...
These calculations find application in many different areas of chemistry, biology, medicine, and geology. For example, many compounds used for medication are weak acids or bases, and a knowledge of the p K a values, together with the octanol-water partition coefficient , can be used for estimating the extent to which the compound enters the ...
For example, to find the K value of methane at 100 psia and 60 °F. On the left-hand vertical axis, locate and mark the point containing the pressure 100 psia. On the right-hand vertical axis, locate and mark the point containing the temperature 60°F. Connect the points with a straight line. Note where the line crosses the methane axis.