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2. FYI, you can get 50% off everything at Old Navy right now

   www.aol.com/lifestyle/you-can-get-half-off...

   $20 $40 Save $20. See at Old Navy ... Oct. 23 you can save 50% — yes, half-off! — absolutely everything at Old Navy. ... that's just one small slice of everything you'll find that's on sale at ...

3. Coupon - Wikipedia

   en.wikipedia.org/wiki/Coupon

   In marketing, a coupon is a ticket or document that can be redeemed for a financial discount or rebate when purchasing a product. Customarily, coupons are issued by manufacturers of consumer packaged goods [1] or by retailers, to be used in retail stores as a part of sales promotions. They are often widely distributed through mail, coupon ...

4. Ornament (art) - Wikipedia

   en.wikipedia.org/wiki/Ornament_(art)

   Jessica Powers' chapter primarily discusses the Casa Degli Amorini Dorati in Pompeii, where 18 wall ornaments were found, the most of any Pompeiian home. Interior wall ornament in a Pompeian home would typically divide the wall into three or more sections under which there would be a dado taking up roughly one-sixth of the height of the wall. [7]

5. Harbor Freight Coupon for 20% Off - AOL

   www.aol.com/news/2011-02-16-harbor-freight...

   Replace old tools or get new ones with this Harbor Freight coupon for 20% off any one item. Expires Feb. 19, 2011. Valid in store, online, or over the phone. Use coupon code 74990607 online or ...

6. Jewellery - Wikipedia

   en.wikipedia.org/wiki/Jewellery

   Like the Greeks, often the purpose of Roman jewellery was to ward off the "evil eye" given by other people. Although women wore a vast array of jewellery, men often only wore a finger ring. Although they were expected to wear at least one ring, some Roman men wore a ring on every finger, while others wore none.

7. Coupon collector's problem - Wikipedia

   en.wikipedia.org/wiki/Coupon_collector's_problem

   An alternative statement is: given n coupons, how many coupons do you expect you need to draw with replacement before having drawn each coupon at least once? The mathematical analysis of the problem reveals that the expected number of trials needed grows as Θ ( n log ⁡ ( n ) ) {\displaystyle \Theta (n\log(n))} .