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An asynchronous (ripple) counter is a "chain" of toggle (T) flip-flops in which the least-significant flip-flop (bit 0) is clocked by an external signal (the counter input clock), and all other flip-flops are clocked by the output of the nearest, less significant flip-flop (e.g., bit 0 clocks the bit 1 flip-flop, bit 1 clocks the bit 2 flip ...
For power-of-2 integer division, a simple binary counter can be used, clocked by the input signal. The least-significant output bit alternates at 1/2 the rate of the input clock, the next bit at 1/4 the rate, the third bit at 1/8 the rate, etc. An arrangement of flipflops is a classic method for integer-n division. Such division is frequency ...
Design an Elliptic filter with a pass band ripple of 1 dB from 0 to 1 rad/sec and a stop band ripple of 40 dB from at least 1.25 rad/sec to . Applying the calculations above for the value for n prior to applying the ceil() function, n is found to be 4.83721900 rounded up to the next integer, 5, by applying the ceil() function, which means a 5 ...
The counter itself must count in Gray code, or if the counter runs in binary then the output value from the counter must be reclocked after it has been converted to Gray code, because when a value is converted from binary to Gray code, [nb 1] it is possible that differences in the arrival times of the binary data bits into the binary-to-Gray ...
The ripple counter section talks exclusively about D-type flip flops, but the diagram has JK-type flip flops, if the diagram were a D-type flip flop, it may make more sense for the section. 152.2.88.109 ( talk ) 14:15, 12 November 2008 (UTC) [ reply ]
The carry-select adder generally consists of ripple-carry adders and a multiplexer.Adding two n-bit numbers with a carry-select adder is done with two adders (therefore two ripple-carry adders), in order to perform the calculation twice, one time with the assumption of the carry-in being zero and the other assuming it will be one.
An example of a list that proves this point is the list (2,3,4,5,1), which would only need to go through one pass of cocktail sort to become sorted, but if using an ascending bubble sort would take four passes. However one cocktail sort pass should be counted as two bubble sort passes.
The order of a Chebyshev filter is equal to the number of reactive components (for example, inductors) needed to realize the filter using analog electronics. An even steeper roll-off can be obtained if ripple is allowed in the stopband, by allowing zeros on the -axis in the complex plane. While this produces near-infinite suppression at and ...