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  2. The two main ways to do this are using the method valueOf() and method parseInt() of the Integer class. Suppose you are given a String like this. String numberInString = "999"; Then you can convert it into integer by using. int numberInInteger = Integer.parseInt(numberInString); And alternatively, you can use.

  3. Java - Convert integer to string - Stack Overflow

    stackoverflow.com/questions/5071040

    Integer class has static method toString() - you can use it: int i = 1234; String str = Integer.toString(i); Returns a String object representing the specified integer. The argument is converted to signed decimal representation and returned as a string, exactly as if the argument and radix 10 were given as arguments to the toString(int, int ...

  4. Or even another alternative is to use Java's built-in java.text.NumberFormat object to see if, after parsing the string the parser position is at the end of the string. If it is, we can assume the entire string is numeric: public static boolean isNumeric(String str) {. ParsePosition pos = new ParsePosition(0); NumberFormat.getInstance().parse ...

  5. Only use Integer.parserInt() after you ensured, that the String really contains an integer value. If doing so and Integer.parseInt still throws an exception, then you know that you have a problem in your code which you should fix (or, for the sake of completeness, that Integer.parseInt itself is buggy, but this option is quite unlikely) –

  6. Your best bet is to use Integer.parseInt. This will return an int, but this can be auto-boxed to an Integer. This is slightly faster than valueOf, as when your numbers are between -128 and 127 it will use the Integer cache and not create new objects. The slowest is the Apache method. private String data = "99";

  7. ByException - integer data: 45 ByException - non-integer data: 465 ByRegex - integer data: 272 ByRegex - non-integer data: 131 ByCompiledRegex - integer data: 45 ByCompiledRegex - non-integer data: 26 ByJonas - integer data: 8 ByJonas - non-integer data: 2

  8. Instead of using String.format (**). it's good if you use DecimalFormat java API which builds for this type of purposes.Let me explain with code. String pattern = "000"; double value = 12; //can be 536 or any. DecimalFormat formatter = new DecimalFormat(pattern); String formattedNumber = formatter.format(value);

  9. How to determine whether a string contains an integer?

    stackoverflow.com/questions/4388546

    Cannot convert String to Integer in Java-1. Find average of numbers in text file. 0.

  10. Actually, int result = a * 10000 + b * 1000 + c * 100 + d * 10 + e; String s = Integer.toString(result); will work. Note: this will only work when a is greater than 0 and all of b, c, d and e are in [0, 9]. For example, if b is 15, Michael's method will get you the result you probably want. edited Apr 20, 2010 at 11:54.

  11. java - Convert hex string to int - Stack Overflow

    stackoverflow.com/questions/11194513

    The maximum value that a Java Integer can handle is 2147483657, or 2^31-1. The hexadecimal number AA0F245C ...