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The molar mass of atoms of an element is given by the relative atomic mass of the element multiplied by the molar mass constant, M u ≈ 1.000 000 × 10 −3 kg/mol ≈ 1 g/mol. For normal samples from Earth with typical isotope composition, the atomic weight can be approximated by the standard atomic weight [ 2 ] or the conventional atomic weight.
Molar mass of glass component, g/mol Batch component Formula of batch component Molar mass of batch component, g/mol SiO 2: 67 60.0843 Sand SiO 2: 60.0843 Na 2 O 12 61.9789 Trona: Na 3 H(CO 3) 2 *2H 2 O 226.0262 CaO 10 56.0774 Lime CaCO 3: 100.0872 Al 2 O 3: 5 101.9613 Albite: Na 2 O*Al 2 O 3 *6SiO 2: 524.4460 K 2 O 1 94.1960 Orthoclase: K 2 O ...
Atomic number Element Molar mass Formal standard atomic weight s.a.w., formal short Note Z calculated; g·mol −1 A r, standard [2] A r, abridged and conventional [2]; C 9 H 8 O 4: 180.159 g·mol −1
The molecular mass and relative molecular mass are distinct from but related to the molar mass. The molar mass is defined as the mass of a given substance divided by the amount of the substance, and is expressed in grams per mol (g/mol). That makes the molar mass an average of many particles or molecules (potentially containing different ...
potassium permanganate has a molar mass of 158.034(1) g mol −1, and reacts with five moles of electrons per mole of potassium permanganate, so its equivalent weight is 158.034(1) g mol −1 /5 eq mol −1 = 31.6068(3) g eq −1.
The term molality is formed in analogy to molarity which is the molar concentration of a solution. The earliest known use of the intensive property molality and of its adjectival unit, the now-deprecated molal, appears to have been published by G. N. Lewis and M. Randall in the 1923 publication of Thermodynamics and the Free Energies of Chemical Substances. [3]
The mass average molar mass is calculated by ¯ = where N i is the number of molecules of molecular mass M i. The mass average molecular mass can be determined by static light scattering , small angle neutron scattering , X-ray scattering , and sedimentation velocity .
In water solutions containing relatively small quantities of dissolved solute (as in biology), such figures may be "percentivized" by multiplying by 100 a ratio of grams solute per mL solution. The result is given as "mass/volume percentage". Such a convention expresses mass concentration of 1 gram of solute in 100 mL of solution, as "1 m/v %".