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In which pO 2 is the chosen maximum partial pressure of oxygen in atmospheres absolute and the FO 2 is the fraction of oxygen in the mixture. For example, if a gas contains 36% oxygen (FO 2 = 0.36) and the limiting maximum pO 2 is chosen at 1.4 atmospheres absolute, the MOD in feet of seawater (fsw) [ Notes 1 ] is 33 fsw/atm x [(1.4 ata / 0.36 ...
We say that 15 is congruent to 3 modulo 12, written 15 ≡ 3 (mod 12), so that 7 + 8 ≡ 3 (mod 12). Similarly, 8:00 represents a period of 8 hours, and twice this would give 16:00, which reads as 4:00 on the clock face, written as 2 × 8 ≡ 4 (mod 12).
The constants R mod N and R 3 mod N can be generated as REDC(R 2 mod N) and as REDC((R 2 mod N)(R 2 mod N)). The fundamental operation is to compute REDC of a product. When standalone REDC is needed, it can be computed as REDC of a product with 1 mod N. The only place where a direct reduction modulo N is necessary is in the precomputation of R ...
c ≡ 4 13 (mod 497) One could use a calculator to compute 4 13; this comes out to 67,108,864. Taking this value modulo 497, the answer c is determined to be 445.
Then () = means that the order of the group is 8 (i.e., there are 8 numbers less than 20 and coprime to it); () = means the order of each element divides 4, that is, the fourth power of any number coprime to 20 is congruent to 1 (mod 20).
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However, the linear congruence 4x ≡ 6 (mod 10) has two solutions, namely, x = 4 and x = 9. The gcd(4, 10) = 2 and 2 does not divide 5, but does divide 6. Since gcd(3, 10) = 1, the linear congruence 3x ≡ 1 (mod 10) will have solutions, that is, modular multiplicative inverses of 3 modulo 10 will exist. In fact, 7 satisfies this congruence (i ...
(2/3 e)—Charge of up, charm and top quarks [2] 1.602 × 10 −19 C: The elementary charge e, i.e. the negative charge on a single electron or the positive charge on a single proton [3] 10 −18: atto-(aC) ~ 1.8755 × 10 −18 C: Planck charge [4] [5] 10 −17: 1.473 × 10 −17 C (92 e) – Positive charge on a uranium nucleus (derived: 92 x ...