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To calculate a percentage of a percentage, convert both percentages to fractions of 100, or to decimals, and multiply them. For example, 50% of 40% is: 50 / 100 × 40 / 100 = 0.50 × 0.40 = 0.20 = 20 / 100 = 20%. It is not correct to divide by 100 and use the percent sign at the same time; it would literally imply ...
Every 1.38 million years (twice in history of humankind) μ ± 6.5σ: 0.999 999 999 919 680: 8.032 × 10 −11 = 0.080 32 ppb = 80.32 ppt: 1 in 12 450 197 393: Every 34 million years (twice since the extinction of dinosaurs) μ ± 7σ: 0.999 999 999 997 440: 2.560 × 10 −12 = 2.560 ppt: 1 in 390 682 215 445: Every 1.07 billion years (four ...
6 1 2 1 1 −1 4 5 9. and would be written in modern notation as 6 1 / 4 , 1 1 / 5 , and 2 − 1 / 9 (i.e., 1 8 / 9 ). The horizontal fraction bar is first attested in the work of Al-Hassār (fl. 1200), [35] a Muslim mathematician from Fez, Morocco, who specialized in Islamic inheritance jurisprudence.
For example, 1 / 4 , 5 / 6 , and −101 / 100 are all irreducible fractions. On the other hand, 2 / 4 is reducible since it is equal in value to 1 / 2 , and the numerator of 1 / 2 is less than the numerator of 2 / 4 . A fraction that is reducible can be reduced by dividing both the numerator ...
0.3 6: Octal: 0.4 8: Duodecimal: 0.6 12: ... It is an irreducible fraction with a numerator of 1 and a ... A number raised to the power of one half is equal to its ...
In terms of partition, 20 / 5 means the size of each of 5 parts into which a set of size 20 is divided. For example, 20 apples divide into five groups of four apples, meaning that "twenty divided by five is equal to four". This is denoted as 20 / 5 = 4, or 20 / 5 = 4. [2] In the example, 20 is the dividend, 5 is the divisor, and 4 is ...
Meanwhile, our lending portfolio more than doubled during the year to $6.1 billion, a 22% sequential gain, also on an FX-neutral basis. Lending continues outpacing credit cards, reaching 29% of ...
where c 1 = 1 / a 1 , c 2 = a 1 / a 2 , c 3 = a 2 / a 1 a 3 , and in general c n+1 = 1 / a n+1 c n . Second, if none of the partial denominators b i are zero we can use a similar procedure to choose another sequence { d i } to make each partial denominator a 1: