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Total combinations using the bits that can be changed - 2^7. Therefore the range of Class A ip address starts from 0 and ends at 127. Explanation 2. Class B has a default mask of 16 bits that translates to 255.255.0.0 in decimal as follows. Class B. 1st Octet. 1st eight bits. out of 32 bits. 2nd Octet.
Edited by Admin February 16, 2020 at 5:13 AM. if we take /23 notation for 172.16.0.0 class B network,we will get 128 network and 510 hosts.Here we are borrowing 7 bit for network and 9 bit for host (2^7=128 and 2^9=512) So each network having 510 host. Starting & ending ip would be 172.16.0.1 to 172.16.1.254.
The Cisco Learning Network has developed an IPv4 subnet chart to help aid in your learning. This chart organizes Class A, B, and C networks and various subnets. The chart displays slash (/) notation (a compact representation of the associated routing prefix), netmask (32-bit mask used to divide an IP address into subnets and specify the network ...
The Class B address structure defines 16 bits for the network parts. Including the 172.16.0.0, therefore you need to do 31 minus 15 = 16 classful class B networks. The class C address in the table, you are also dealing with a range of private classful class C address.
Edited by Admin February 16, 2020 at 4:39 AM. Tuan, The addresses 192.168.0.0 to 192.168.255.255 fall into class B of IP addresses. For the purposes of private IP addressing, all 256 class C networks have been allocated in RFC1918. The entire range can be summarized using a supernet address of 192.168.0.0/16.
The answer with 8 network bits cannot be correct because the question states that a Class B network is used, so the number of network bits must always be 16. The two correct answers have 16 network bits (required because the question states the use of a Class B network), and at least 7 subnet and host bits each. A and C are correct.
Classless Addressing: All IP addresses other then the above prefix lenghts are called classless. But there is a condition to use it, mean you must be use a longer/equal prefix lenght for it from there own prefix lenght. Let supose you have an address 172.17.2.15 then you use 16 or greater prefix lenght. the one you use i.e, /6 is invaild.
If I have a class C network in action and VoIP phones also using the same subnet class C scope would it be possible just to convert the network to a class B or would the preferred method be to vlan them up? Say my user network on 172.0.0.0/16 and phones on 172.0.1.0/16, they should still be able to talk to each other right?
Subnetting a Class B network address - TechRepublic . Example 6: The Class B 255.255.255.128 subnet mask:
Class B is if the first 2 bits are 10, which means the only numbers that can be made are between 128-191. Again if you look at the decimal weights of each binary position, those are the only numbers that can be made if you lock the first 2 bits of the first octet to 10. 10000000 - 10111111. Class C is if the first 3 bits are 110 which gives us ...